假如有這樣的一段序列:
1 2
1 2
2 1
1 3
1 4
1 5
4 1
我們需要得到如下的結(jié)果:
1 3
1 5
2 1
4 1
那么,請借助以下的perl腳本來實現(xiàn)。
代碼一:
my %hash;
my $script = $0; # Get the script name
sub usage
{
printf("Usage:\n");
printf("perl $script source_file> dest_file>\n");
}
# If the number of parameters less than 2 ,exit the script
if ( $#ARGV+1 2) {
usage;
exit 0;
}
my $source_file = $ARGV[0]; #File need to remove duplicate rows
my $dest_file = $ARGV[1]; # File after remove duplicates rows
open (FILE,"$source_file") or die "Cannot open file $!\n";
open (SORTED,">$dest_file") or die "Cannot open file $!\n";
while(defined (my $line = FILE>))
{
chomp($line);
$hash{$line} += 1;
# print "$line,$hash{$line}\n";
}
foreach my $k (keys %hash) {
print SORTED "$k,$hash{$k}\n";#改行打印出列和該列出現(xiàn)的次數(shù)到目標文件
}
close (FILE);
close (SORTED);
代碼三:
通過perl腳本,刪除數(shù)據(jù)組中重復的字段