由于之前的業(yè)務(wù)，造成數(shù)據(jù)庫上產(chǎn)生了臟數(shù)據(jù)，寫個腳本刪除重復(fù)的數(shù)據(jù)。由于是開發(fā)測試環(huán)境，所以選擇任意刪除相同uid中的一條。由于每次執(zhí)行只刪除重復(fù)數(shù)據(jù)的一條，需要重復(fù)執(zhí)行，如果本輪沒有數(shù)據(jù)被刪就OK
#!/bin/sh
# delete all company's duplicate uid
MYSQL_BIN_PATH=/data/mysql/server/mysql_3306/bin
MYSQL_SOCK_PATH=/data/mysql/server/mysql_3306/tmp
DBUSER=dbuser
DBPWD=userpwd
DBHOSTNAME=192.168.1.105
PORT=3306
# get all company_id
for company_id in `${MYSQL_BIN_PATH}/mysql -u${DBUSER} -p${DBPWD} -h ${DBHOSTNAME} -P ${PORT} --socket=${MYSQL_SOCK_PATH}/mysql.sock -e "
SELECT company_id FROM company.companypage;"`
do
if [ $company_id != "company_id" ] ; then
# if [ $company_id -eq 2733 ] ; then
suffix=`expr ${company_id} % 100`
for user_id in `${MYSQL_BIN_PATH}/mysql -u${DBUSER} -p${DBPWD} -h ${DBHOSTNAME} -P ${PORT} --socket=${MYSQL_SOCK_PATH}/mysql.sock -e "
SELECT user_id FROM company.company_candidate_${suffix} WHERE company_id=${company_id} AND user_id>0 GROUP BY company_id, user_id HAVING COUNT(user_id) > 1;"`
do
if [ $user_id != "user_id" ] ; then
${MYSQL_BIN_PATH}/mysql -u${DBUSER} -p${DBPWD} -h ${DBHOSTNAME} -P ${PORT} --socket=${MYSQL_SOCK_PATH}/mysql.sock -e "
DELETE FROM company.company_candidate_${suffix} WHERE company_id=${company_id} and user_id=${user_id} limit 1;"
echo "delete from company_candidate_${suffix} where company_id=${company_id} and user_id=${user_id} limit 1"
fi
done
# fi
fi
done
exit 0
總結(jié)
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